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Watt/centimeter/°C to Btu (IT) inch/hour/sq. foot/°F

Values for calculation

$ \{\text{Value}\in\mathbb{R}\} $
This set includes all real numbers.
$ \text{Value} $

Thermal conductivity converter

Thermal conductivity converter from watt/centimeter/°C to Btu (IT) inch/hour/sq. foot/°F

$$ 1\ \mathrm{W/(cm\cdot\ °C)}=\cfrac{\cfrac{1}{10^{-2}}}{519.22039991/3600}\ \mathrm{Btu\ (IT)\ inch/(h\cdot\ ft^2\cdot\ °F)}=693.3\ \mathrm{Btu\ (IT)\ inch/(h\cdot\ ft^2\cdot\ °F)} $$
$ 693.34717985349\ \mathrm{Btu\ (IT)\ inch/(h\cdot\ ft^2\cdot\ °F)} $
Unrounded result
693.34717985349
$1\ \mathrm{W/(cm\cdot\ °C)}=\cfrac{\cfrac{1}{10^{-2}}}{519.22039991/3600}\ \mathrm{Btu\ (IT)\ inch/(h\cdot\ ft^2\cdot\ °F)}=693.3\ \mathrm{Btu\ (IT)\ inch/(h\cdot\ ft^2\cdot\ °F)}$
Equations in LaTeX code
1\ \mathrm{W/(cm\cdot\ °C)}=\cfrac{\cfrac{1}{10^{-2}}}{519.22039991/3600}\ \mathrm{Btu\ (IT)\ inch/(h\cdot\ ft^2\cdot\ °F)}=693.3\ \mathrm{Btu\ (IT)\ inch/(h\cdot\ ft^2\cdot\ °F)}
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