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Kilocalorie (IT)/hour/meter/°C to Btu (IT) inch/hour/sq. foot/°F

Values for calculation

$ \text{Value} $

Thermal conductivity converter

Thermal conductivity converter from kilocalorie (IT)/hour/meter/°C to Btu (IT) inch/hour/sq. foot/°F

$$ 1\ \mathrm{kcal\ (IT)/(h\cdot\ m\cdot\ °C)}=\cfrac{{1}\cdot{418.68/60/60\cdot 10}}{519.22039991/3600}\ \mathrm{Btu\ (IT)\ inch/(h\cdot\ ft^2\cdot\ °F)}=8.06\ \mathrm{Btu\ (IT)\ inch/(h\cdot\ ft^2\cdot\ °F)} $$