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Calorie (IT)/gram/°F to Btu (IT)/pound/°F

Values for calculation

$ \text{Value} $

Specific heat capacity converter

Specific heat capacity converter from calorie (IT)/gram/°F to Btu (IT)/pound/°F

$$ 1\ \mathrm{cal\ (IT)/g/°F}=\cfrac{{1}\cdot{4186.8}}{4186.8}\ \mathrm{Btu\ (IT)/lb/°F}=1\ \mathrm{Btu\ (IT)/lb/°F} $$