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Joule/gram/°C to calorie (IT)/gram/°F

Values for calculation

$ \text{Value} $

Specific heat capacity converter

Specific heat capacity converter from joule/gram/°C to calorie (IT)/gram/°F

$$ 1\ \mathrm{J/(g\cdot\ °C)}=\cfrac{\cfrac{1}{10^{-3}}}{4186.8}\ \mathrm{cal\ (IT)/g/°F}=0.2388\ \mathrm{cal\ (IT)/g/°F} $$