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Horsepower (550 ft·lbf/s) to kilojoule/hour

Values for calculation

$ \{\text{Value}\in\mathbb{R}\} $
This set includes all real numbers.
$ \text{Value} $

Power converter

Power converter from horsepower (550 ft·lbf/s) to kilojoule/hour

$$ 1\ \mathrm{hp\ (550\ ft\cdot\ lbf/s)}={\cfrac{1}{0.0013410221}}\cdot{3.6}\ \mathrm{kJ/h}=2684.5\ \mathrm{kJ/h} $$
$ 2684.519516867\ \mathrm{kJ/h} $
Unrounded result
2684.519516867
$1\ \mathrm{hp\ (550\ ft\cdot\ lbf/s)}={\cfrac{1}{0.0013410221}}\cdot{3.6}\ \mathrm{kJ/h}=2684.5\ \mathrm{kJ/h}$
Equations in LaTeX code
1\ \mathrm{hp\ (550\ ft\cdot\ lbf/s)}={\cfrac{1}{0.0013410221}}\cdot{3.6}\ \mathrm{kJ/h}=2684.5\ \mathrm{kJ/h}
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