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Calorie (IT)/gram/°F to joule/kilogram/K

Values for calculation

$ \text{Value} $

Specific heat capacity converter

Specific heat capacity converter from calorie (IT)/gram/°F to joule/kilogram/K

$$ 1\ \mathrm{cal\ (IT)/g/°F}={1}\cdot{4186.8}\ \mathrm{J/(kg\cdot\ K)}=4186.8\ \mathrm{J/(kg\cdot\ K)} $$