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Specific heat capacity

Values for calculation

$ \{\text{Value}\in\mathbb{R}\} $
This set includes all real numbers.
$ \text{Value} $

Specific heat capacity converter

Specific heat capacity converter from joule/kilogram/K to joule/kilogram/°C

$$ 1\ \mathrm{J/(kg\cdot\ K)}={1}\ \mathrm{J/(kg\cdot\ °C)}=1\ \mathrm{J/(kg\cdot\ °C)} $$
$ 1\ \mathrm{J/(kg\cdot\ °C)} $
Unrounded result
1
$1\ \mathrm{J/(kg\cdot\ K)}={1}\ \mathrm{J/(kg\cdot\ °C)}=1\ \mathrm{J/(kg\cdot\ °C)}$
Equations in LaTeX code
1\ \mathrm{J/(kg\cdot\ K)}={1}\ \mathrm{J/(kg\cdot\ °C)}=1\ \mathrm{J/(kg\cdot\ °C)}

Specific heat capacity converter from joule/kilogram/K to joule/gram/°C

$$ 1\ \mathrm{J/(kg\cdot\ K)}={1}\cdot{10^{-3}}\ \mathrm{J/(g\cdot\ °C)}=0.001\ \mathrm{J/(g\cdot\ °C)} $$
$ 0.001\ \mathrm{J/(g\cdot\ °C)} $
Unrounded result
0.001
$1\ \mathrm{J/(kg\cdot\ K)}={1}\cdot{10^{-3}}\ \mathrm{J/(g\cdot\ °C)}=0.001\ \mathrm{J/(g\cdot\ °C)}$
Equations in LaTeX code
1\ \mathrm{J/(kg\cdot\ K)}={1}\cdot{10^{-3}}\ \mathrm{J/(g\cdot\ °C)}=0.001\ \mathrm{J/(g\cdot\ °C)}

Specific heat capacity converter from joule/kilogram/K to kilojoule/kilogram/K

$$ 1\ \mathrm{J/(kg\cdot\ K)}={1}\cdot{10^{-3}}\ \mathrm{kJ/(kg\cdot\ K)}=0.001\ \mathrm{kJ/(kg\cdot\ K)} $$
$ 0.001\ \mathrm{kJ/(kg\cdot\ K)} $
Unrounded result
0.001
$1\ \mathrm{J/(kg\cdot\ K)}={1}\cdot{10^{-3}}\ \mathrm{kJ/(kg\cdot\ K)}=0.001\ \mathrm{kJ/(kg\cdot\ K)}$
Equations in LaTeX code
1\ \mathrm{J/(kg\cdot\ K)}={1}\cdot{10^{-3}}\ \mathrm{kJ/(kg\cdot\ K)}=0.001\ \mathrm{kJ/(kg\cdot\ K)}

Specific heat capacity converter from joule/kilogram/K to kilojoule/kilogram/°C

$$ 1\ \mathrm{J/(kg\cdot\ K)}={1}\cdot{10^{-3}}\ \mathrm{kJ/(kg\cdot\ °C)}=0.001\ \mathrm{kJ/(kg\cdot\ °C)} $$
$ 0.001\ \mathrm{kJ/(kg\cdot\ °C)} $
Unrounded result
0.001
$1\ \mathrm{J/(kg\cdot\ K)}={1}\cdot{10^{-3}}\ \mathrm{kJ/(kg\cdot\ °C)}=0.001\ \mathrm{kJ/(kg\cdot\ °C)}$
Equations in LaTeX code
1\ \mathrm{J/(kg\cdot\ K)}={1}\cdot{10^{-3}}\ \mathrm{kJ/(kg\cdot\ °C)}=0.001\ \mathrm{kJ/(kg\cdot\ °C)}

Specific heat capacity converter from joule/kilogram/K to calorie (IT)/gram/°C

$$ 1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4186.8}\ \mathrm{cal\ (IT)/g/°C}=0.0002388\ \mathrm{cal\ (IT)/g/°C} $$
$ 0.0002388458966275\ \mathrm{cal\ (IT)/g/°C} $
Unrounded result
0.0002388458966275
$1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4186.8}\ \mathrm{cal\ (IT)/g/°C}=0.0002388\ \mathrm{cal\ (IT)/g/°C}$
Equations in LaTeX code
1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4186.8}\ \mathrm{cal\ (IT)/g/°C}=0.0002388\ \mathrm{cal\ (IT)/g/°C}

Specific heat capacity converter from joule/kilogram/K to calorie (IT)/gram/°F

$$ 1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4186.8}\ \mathrm{cal\ (IT)/g/°F}=0.0002388\ \mathrm{cal\ (IT)/g/°F} $$
$ 0.0002388458966275\ \mathrm{cal\ (IT)/g/°F} $
Unrounded result
0.0002388458966275
$1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4186.8}\ \mathrm{cal\ (IT)/g/°F}=0.0002388\ \mathrm{cal\ (IT)/g/°F}$
Equations in LaTeX code
1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4186.8}\ \mathrm{cal\ (IT)/g/°F}=0.0002388\ \mathrm{cal\ (IT)/g/°F}

Specific heat capacity converter from joule/kilogram/K to calorie (th)/gram/°C

$$ 1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4184}\ \mathrm{cal\ (th)/g/°C}=0.000239\ \mathrm{cal\ (th)/g/°C} $$
$ 0.00023900573613767\ \mathrm{cal\ (th)/g/°C} $
Unrounded result
0.00023900573613767
$1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4184}\ \mathrm{cal\ (th)/g/°C}=0.000239\ \mathrm{cal\ (th)/g/°C}$
Equations in LaTeX code
1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4184}\ \mathrm{cal\ (th)/g/°C}=0.000239\ \mathrm{cal\ (th)/g/°C}

Specific heat capacity converter from joule/kilogram/K to kilocalorie (IT)/kilogram/°C

$$ 1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4186.8}\ \mathrm{kcal\ (IT)/kg/°C}=0.0002388\ \mathrm{kcal\ (IT)/kg/°C} $$
$ 0.0002388458966275\ \mathrm{kcal\ (IT)/kg/°C} $
Unrounded result
0.0002388458966275
$1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4186.8}\ \mathrm{kcal\ (IT)/kg/°C}=0.0002388\ \mathrm{kcal\ (IT)/kg/°C}$
Equations in LaTeX code
1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4186.8}\ \mathrm{kcal\ (IT)/kg/°C}=0.0002388\ \mathrm{kcal\ (IT)/kg/°C}

Specific heat capacity converter from joule/kilogram/K to kilocalorie (th)/kilogram/°C

$$ 1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4184}\ \mathrm{kcal\ (th)/kg/°C}=0.000239\ \mathrm{kcal\ (th)/kg/°C} $$
$ 0.00023900573613767\ \mathrm{kcal\ (th)/kg/°C} $
Unrounded result
0.00023900573613767
$1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4184}\ \mathrm{kcal\ (th)/kg/°C}=0.000239\ \mathrm{kcal\ (th)/kg/°C}$
Equations in LaTeX code
1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4184}\ \mathrm{kcal\ (th)/kg/°C}=0.000239\ \mathrm{kcal\ (th)/kg/°C}

Specific heat capacity converter from joule/kilogram/K to kilocalorie (IT)/kilogram/K

$$ 1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4186.8}\ \mathrm{kcal\ (IT)/kg/K}=0.0002388\ \mathrm{kcal\ (IT)/kg/K} $$
$ 0.0002388458966275\ \mathrm{kcal\ (IT)/kg/K} $
Unrounded result
0.0002388458966275
$1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4186.8}\ \mathrm{kcal\ (IT)/kg/K}=0.0002388\ \mathrm{kcal\ (IT)/kg/K}$
Equations in LaTeX code
1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4186.8}\ \mathrm{kcal\ (IT)/kg/K}=0.0002388\ \mathrm{kcal\ (IT)/kg/K}

Specific heat capacity converter from joule/kilogram/K to kilocalorie (th)/kilogram/K

$$ 1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4184}\ \mathrm{kcal\ (th)/kg/K}=0.000239\ \mathrm{kcal\ (th)/kg/K} $$
$ 0.00023900573613767\ \mathrm{kcal\ (th)/kg/K} $
Unrounded result
0.00023900573613767
$1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4184}\ \mathrm{kcal\ (th)/kg/K}=0.000239\ \mathrm{kcal\ (th)/kg/K}$
Equations in LaTeX code
1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4184}\ \mathrm{kcal\ (th)/kg/K}=0.000239\ \mathrm{kcal\ (th)/kg/K}

Specific heat capacity converter from joule/kilogram/K to kilogram-force meter/kilogram/K

$$ 1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{9.80665}\ \mathrm{kgf\cdot\ m/kg/K}=0.102\ \mathrm{kgf\cdot\ m/kg/K} $$
$ 0.10197162129779\ \mathrm{kgf\cdot\ m/kg/K} $
Unrounded result
0.10197162129779
$1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{9.80665}\ \mathrm{kgf\cdot\ m/kg/K}=0.102\ \mathrm{kgf\cdot\ m/kg/K}$
Equations in LaTeX code
1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{9.80665}\ \mathrm{kgf\cdot\ m/kg/K}=0.102\ \mathrm{kgf\cdot\ m/kg/K}

Specific heat capacity converter from joule/kilogram/K to pound-force foot/pound/°R

$$ 1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{5.380320456}\ \mathrm{lbf\cdot\ ft/pound/°R}=0.1859\ \mathrm{lbf\cdot\ ft/pound/°R} $$
$ 0.18586253517387\ \mathrm{lbf\cdot\ ft/pound/°R} $
Unrounded result
0.18586253517387
$1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{5.380320456}\ \mathrm{lbf\cdot\ ft/pound/°R}=0.1859\ \mathrm{lbf\cdot\ ft/pound/°R}$
Equations in LaTeX code
1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{5.380320456}\ \mathrm{lbf\cdot\ ft/pound/°R}=0.1859\ \mathrm{lbf\cdot\ ft/pound/°R}

Specific heat capacity converter from joule/kilogram/K to Btu (IT)/pound/°F

$$ 1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4186.8}\ \mathrm{Btu\ (IT)/lb/°F}=0.0002388\ \mathrm{Btu\ (IT)/lb/°F} $$
$ 0.0002388458966275\ \mathrm{Btu\ (IT)/lb/°F} $
Unrounded result
0.0002388458966275
$1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4186.8}\ \mathrm{Btu\ (IT)/lb/°F}=0.0002388\ \mathrm{Btu\ (IT)/lb/°F}$
Equations in LaTeX code
1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4186.8}\ \mathrm{Btu\ (IT)/lb/°F}=0.0002388\ \mathrm{Btu\ (IT)/lb/°F}

Specific heat capacity converter from joule/kilogram/K to Btu (th)/pound/°F

$$ 1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4184}\ \mathrm{Btu\ (th)/lb/°F}=0.000239\ \mathrm{Btu\ (th)/lb/°F} $$
$ 0.00023900573613767\ \mathrm{Btu\ (th)/lb/°F} $
Unrounded result
0.00023900573613767
$1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4184}\ \mathrm{Btu\ (th)/lb/°F}=0.000239\ \mathrm{Btu\ (th)/lb/°F}$
Equations in LaTeX code
1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4184}\ \mathrm{Btu\ (th)/lb/°F}=0.000239\ \mathrm{Btu\ (th)/lb/°F}

Specific heat capacity converter from joule/kilogram/K to Btu (IT)/pound/°R

$$ 1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4186.8}\ \mathrm{Btu\ (IT)/lb/°R}=0.0002388\ \mathrm{Btu\ (IT)/lb/°R} $$
$ 0.0002388458966275\ \mathrm{Btu\ (IT)/lb/°R} $
Unrounded result
0.0002388458966275
$1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4186.8}\ \mathrm{Btu\ (IT)/lb/°R}=0.0002388\ \mathrm{Btu\ (IT)/lb/°R}$
Equations in LaTeX code
1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4186.8}\ \mathrm{Btu\ (IT)/lb/°R}=0.0002388\ \mathrm{Btu\ (IT)/lb/°R}

Specific heat capacity converter from joule/kilogram/K to Btu (th)/pound/°R

$$ 1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4184}\ \mathrm{Btu\ (th)/lb/°R}=0.000239\ \mathrm{Btu\ (th)/lb/°R} $$
$ 0.00023900573613767\ \mathrm{Btu\ (th)/lb/°R} $
Unrounded result
0.00023900573613767
$1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4184}\ \mathrm{Btu\ (th)/lb/°R}=0.000239\ \mathrm{Btu\ (th)/lb/°R}$
Equations in LaTeX code
1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4184}\ \mathrm{Btu\ (th)/lb/°R}=0.000239\ \mathrm{Btu\ (th)/lb/°R}

Specific heat capacity converter from joule/kilogram/K to Btu (IT)/pound/°C

$$ 1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{2326}\ \mathrm{Btu\ (IT)/lb/°C}=0.0004299\ \mathrm{Btu\ (IT)/lb/°C} $$
$ 0.00042992261392949\ \mathrm{Btu\ (IT)/lb/°C} $
Unrounded result
0.00042992261392949
$1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{2326}\ \mathrm{Btu\ (IT)/lb/°C}=0.0004299\ \mathrm{Btu\ (IT)/lb/°C}$
Equations in LaTeX code
1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{2326}\ \mathrm{Btu\ (IT)/lb/°C}=0.0004299\ \mathrm{Btu\ (IT)/lb/°C}

Specific heat capacity converter from joule/kilogram/K to CHU/pound/°C

$$ 1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4186.8}\ \mathrm{CHU/(lb\cdot\ °C)}=0.0002388\ \mathrm{CHU/(lb\cdot\ °C)} $$
$ 0.0002388458966275\ \mathrm{CHU/(lb\cdot\ °C)} $
Unrounded result
0.0002388458966275
$1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4186.8}\ \mathrm{CHU/(lb\cdot\ °C)}=0.0002388\ \mathrm{CHU/(lb\cdot\ °C)}$
Equations in LaTeX code
1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4186.8}\ \mathrm{CHU/(lb\cdot\ °C)}=0.0002388\ \mathrm{CHU/(lb\cdot\ °C)}
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