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Joule/kilogram/K to calorie (IT)/gram/°F

Values for calculation

$ \text{Value} $

Specific heat capacity converter

Specific heat capacity converter from joule/kilogram/K to calorie (IT)/gram/°F

$$ 1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4186.8}\ \mathrm{cal\ (IT)/g/°F}=0.0002388\ \mathrm{cal\ (IT)/g/°F} $$