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Thermal conductivity

Values for calculation

$ \{\text{Value}\in\mathbb{R}\} $
This set includes all real numbers.
$ \text{Value} $

Thermal conductivity converter

Thermal conductivity converter from watt/meter/K to watt/centimeter/°C

$$ 1\ \mathrm{W/(m\cdot\ K)}={1}\cdot{10^{-2}}\ \mathrm{W/(cm\cdot\ °C)}=0.01\ \mathrm{W/(cm\cdot\ °C)} $$
$ 0.01\ \mathrm{W/(cm\cdot\ °C)} $
Unrounded result
0.01
$1\ \mathrm{W/(m\cdot\ K)}={1}\cdot{10^{-2}}\ \mathrm{W/(cm\cdot\ °C)}=0.01\ \mathrm{W/(cm\cdot\ °C)}$
Equations in LaTeX code
1\ \mathrm{W/(m\cdot\ K)}={1}\cdot{10^{-2}}\ \mathrm{W/(cm\cdot\ °C)}=0.01\ \mathrm{W/(cm\cdot\ °C)}

Thermal conductivity converter from watt/meter/K to kilowatt/meter/K

$$ 1\ \mathrm{W/(m\cdot\ K)}={1}\cdot{10^{-3}}\ \mathrm{kW/(m\cdot\ K)}=0.001\ \mathrm{kW/(m\cdot\ K)} $$
$ 0.001\ \mathrm{kW/(m\cdot\ K)} $
Unrounded result
0.001
$1\ \mathrm{W/(m\cdot\ K)}={1}\cdot{10^{-3}}\ \mathrm{kW/(m\cdot\ K)}=0.001\ \mathrm{kW/(m\cdot\ K)}$
Equations in LaTeX code
1\ \mathrm{W/(m\cdot\ K)}={1}\cdot{10^{-3}}\ \mathrm{kW/(m\cdot\ K)}=0.001\ \mathrm{kW/(m\cdot\ K)}

Thermal conductivity converter from watt/meter/K to calorie (IT)/second/cm/°C

$$ 1\ \mathrm{W/(m\cdot\ K)}=\cfrac{1}{418.68}\ \mathrm{cal\ (IT)/(s\cdot\ cm\cdot\ °C)}=0.002388\ \mathrm{cal\ (IT)/(s\cdot\ cm\cdot\ °C)} $$
$ 0.002388458966275\ \mathrm{cal\ (IT)/(s\cdot\ cm\cdot\ °C)} $
Unrounded result
0.002388458966275
$1\ \mathrm{W/(m\cdot\ K)}=\cfrac{1}{418.68}\ \mathrm{cal\ (IT)/(s\cdot\ cm\cdot\ °C)}=0.002388\ \mathrm{cal\ (IT)/(s\cdot\ cm\cdot\ °C)}$
Equations in LaTeX code
1\ \mathrm{W/(m\cdot\ K)}=\cfrac{1}{418.68}\ \mathrm{cal\ (IT)/(s\cdot\ cm\cdot\ °C)}=0.002388\ \mathrm{cal\ (IT)/(s\cdot\ cm\cdot\ °C)}

Thermal conductivity converter from watt/meter/K to calorie (th)/second/cm/°C

$$ 1\ \mathrm{W/(m\cdot\ K)}=\cfrac{1}{418.4}\ \mathrm{cal\ (th)/(s\cdot\ cm\cdot\ °C)}=0.00239\ \mathrm{cal\ (th)/(s\cdot\ cm\cdot\ °C)} $$
$ 0.0023900573613767\ \mathrm{cal\ (th)/(s\cdot\ cm\cdot\ °C)} $
Unrounded result
0.0023900573613767
$1\ \mathrm{W/(m\cdot\ K)}=\cfrac{1}{418.4}\ \mathrm{cal\ (th)/(s\cdot\ cm\cdot\ °C)}=0.00239\ \mathrm{cal\ (th)/(s\cdot\ cm\cdot\ °C)}$
Equations in LaTeX code
1\ \mathrm{W/(m\cdot\ K)}=\cfrac{1}{418.4}\ \mathrm{cal\ (th)/(s\cdot\ cm\cdot\ °C)}=0.00239\ \mathrm{cal\ (th)/(s\cdot\ cm\cdot\ °C)}

Thermal conductivity converter from watt/meter/K to kilocalorie (IT)/hour/meter/°C

$$ 1\ \mathrm{W/(m\cdot\ K)}=\cfrac{1}{418.68/60/60\cdot 10}\ \mathrm{kcal\ (IT)/(h\cdot\ m\cdot\ °C)}=0.86\ \mathrm{kcal\ (IT)/(h\cdot\ m\cdot\ °C)} $$
$ 0.85984522785899\ \mathrm{kcal\ (IT)/(h\cdot\ m\cdot\ °C)} $
Unrounded result
0.85984522785899
$1\ \mathrm{W/(m\cdot\ K)}=\cfrac{1}{418.68/60/60\cdot 10}\ \mathrm{kcal\ (IT)/(h\cdot\ m\cdot\ °C)}=0.86\ \mathrm{kcal\ (IT)/(h\cdot\ m\cdot\ °C)}$
Equations in LaTeX code
1\ \mathrm{W/(m\cdot\ K)}=\cfrac{1}{418.68/60/60\cdot 10}\ \mathrm{kcal\ (IT)/(h\cdot\ m\cdot\ °C)}=0.86\ \mathrm{kcal\ (IT)/(h\cdot\ m\cdot\ °C)}

Thermal conductivity converter from watt/meter/K to kilocalorie (th)/hour/meter/°C

$$ 1\ \mathrm{W/(m\cdot\ K)}=\cfrac{1}{418.4/60/60\cdot 10}\ \mathrm{kcal\ (th)/(h\cdot\ m\cdot\ °C)}=0.86\ \mathrm{kcal\ (th)/(h\cdot\ m\cdot\ °C)} $$
$ 0.8604206500956\ \mathrm{kcal\ (th)/(h\cdot\ m\cdot\ °C)} $
Unrounded result
0.8604206500956
$1\ \mathrm{W/(m\cdot\ K)}=\cfrac{1}{418.4/60/60\cdot 10}\ \mathrm{kcal\ (th)/(h\cdot\ m\cdot\ °C)}=0.86\ \mathrm{kcal\ (th)/(h\cdot\ m\cdot\ °C)}$
Equations in LaTeX code
1\ \mathrm{W/(m\cdot\ K)}=\cfrac{1}{418.4/60/60\cdot 10}\ \mathrm{kcal\ (th)/(h\cdot\ m\cdot\ °C)}=0.86\ \mathrm{kcal\ (th)/(h\cdot\ m\cdot\ °C)}

Thermal conductivity converter from watt/meter/K to Btu (IT) inch/second/sq. foot/°F

$$ 1\ \mathrm{W/(m\cdot\ K)}=\cfrac{1}{519.22039991}\ \mathrm{Btu\ (IT)\ inch/(s\cdot\ ft^2\cdot\ °F)}=0.001926\ \mathrm{Btu\ (IT)\ inch/(s\cdot\ ft^2\cdot\ °F)} $$
$ 0.0019259643884819\ \mathrm{Btu\ (IT)\ inch/(s\cdot\ ft^2\cdot\ °F)} $
Unrounded result
0.0019259643884819
$1\ \mathrm{W/(m\cdot\ K)}=\cfrac{1}{519.22039991}\ \mathrm{Btu\ (IT)\ inch/(s\cdot\ ft^2\cdot\ °F)}=0.001926\ \mathrm{Btu\ (IT)\ inch/(s\cdot\ ft^2\cdot\ °F)}$
Equations in LaTeX code
1\ \mathrm{W/(m\cdot\ K)}=\cfrac{1}{519.22039991}\ \mathrm{Btu\ (IT)\ inch/(s\cdot\ ft^2\cdot\ °F)}=0.001926\ \mathrm{Btu\ (IT)\ inch/(s\cdot\ ft^2\cdot\ °F)}

Thermal conductivity converter from watt/meter/K to Btu (th) inch/second/sq. foot/°F

$$ 1\ \mathrm{W/(m\cdot\ K)}=\cfrac{1}{518.87316166}\ \mathrm{Btu\ (th)\ inch/(s\cdot\ ft^2\cdot\ °F)}=0.001927\ \mathrm{Btu\ (th)\ inch/(s\cdot\ ft^2\cdot\ °F)} $$
$ 0.001927253274771\ \mathrm{Btu\ (th)\ inch/(s\cdot\ ft^2\cdot\ °F)} $
Unrounded result
0.001927253274771
$1\ \mathrm{W/(m\cdot\ K)}=\cfrac{1}{518.87316166}\ \mathrm{Btu\ (th)\ inch/(s\cdot\ ft^2\cdot\ °F)}=0.001927\ \mathrm{Btu\ (th)\ inch/(s\cdot\ ft^2\cdot\ °F)}$
Equations in LaTeX code
1\ \mathrm{W/(m\cdot\ K)}=\cfrac{1}{518.87316166}\ \mathrm{Btu\ (th)\ inch/(s\cdot\ ft^2\cdot\ °F)}=0.001927\ \mathrm{Btu\ (th)\ inch/(s\cdot\ ft^2\cdot\ °F)}

Thermal conductivity converter from watt/meter/K to Btu (IT) foot/hour/sq. foot/°F

$$ 1\ \mathrm{W/(m\cdot\ K)}=\cfrac{1}{519.22039991/300}\ \mathrm{Btu\ (th)\ ft/(h\cdot\ ft^2\cdot\ °F)}=0.578\ \mathrm{Btu\ (th)\ ft/(h\cdot\ ft^2\cdot\ °F)} $$
$ 0.57778931654458\ \mathrm{Btu\ (th)\ ft/(h\cdot\ ft^2\cdot\ °F)} $
Unrounded result
0.57778931654458
$1\ \mathrm{W/(m\cdot\ K)}=\cfrac{1}{519.22039991/300}\ \mathrm{Btu\ (th)\ ft/(h\cdot\ ft^2\cdot\ °F)}=0.578\ \mathrm{Btu\ (th)\ ft/(h\cdot\ ft^2\cdot\ °F)}$
Equations in LaTeX code
1\ \mathrm{W/(m\cdot\ K)}=\cfrac{1}{519.22039991/300}\ \mathrm{Btu\ (th)\ ft/(h\cdot\ ft^2\cdot\ °F)}=0.578\ \mathrm{Btu\ (th)\ ft/(h\cdot\ ft^2\cdot\ °F)}

Thermal conductivity converter from watt/meter/K to Btu (th) foot/hour/sq. foot/°F

$$ 1\ \mathrm{W/(m\cdot\ K)}=\cfrac{1}{518.87316166/300}\ \mathrm{Btu\ (th)\ ft/(h\cdot\ ft^2\cdot\ °F)}=0.578\ \mathrm{Btu\ (th)\ ft/(h\cdot\ ft^2\cdot\ °F)} $$
$ 0.57817598243129\ \mathrm{Btu\ (th)\ ft/(h\cdot\ ft^2\cdot\ °F)} $
Unrounded result
0.57817598243129
$1\ \mathrm{W/(m\cdot\ K)}=\cfrac{1}{518.87316166/300}\ \mathrm{Btu\ (th)\ ft/(h\cdot\ ft^2\cdot\ °F)}=0.578\ \mathrm{Btu\ (th)\ ft/(h\cdot\ ft^2\cdot\ °F)}$
Equations in LaTeX code
1\ \mathrm{W/(m\cdot\ K)}=\cfrac{1}{518.87316166/300}\ \mathrm{Btu\ (th)\ ft/(h\cdot\ ft^2\cdot\ °F)}=0.578\ \mathrm{Btu\ (th)\ ft/(h\cdot\ ft^2\cdot\ °F)}

Thermal conductivity converter from watt/meter/K to Btu (IT) inch/hour/sq. foot/°F

$$ 1\ \mathrm{W/(m\cdot\ K)}=\cfrac{1}{519.22039991/3600}\ \mathrm{Btu\ (IT)\ inch/(h\cdot\ ft^2\cdot\ °F)}=6.93\ \mathrm{Btu\ (IT)\ inch/(h\cdot\ ft^2\cdot\ °F)} $$
$ 6.9334717985349\ \mathrm{Btu\ (IT)\ inch/(h\cdot\ ft^2\cdot\ °F)} $
Unrounded result
6.9334717985349
$1\ \mathrm{W/(m\cdot\ K)}=\cfrac{1}{519.22039991/3600}\ \mathrm{Btu\ (IT)\ inch/(h\cdot\ ft^2\cdot\ °F)}=6.93\ \mathrm{Btu\ (IT)\ inch/(h\cdot\ ft^2\cdot\ °F)}$
Equations in LaTeX code
1\ \mathrm{W/(m\cdot\ K)}=\cfrac{1}{519.22039991/3600}\ \mathrm{Btu\ (IT)\ inch/(h\cdot\ ft^2\cdot\ °F)}=6.93\ \mathrm{Btu\ (IT)\ inch/(h\cdot\ ft^2\cdot\ °F)}

Thermal conductivity converter from watt/meter/K to Btu (th) inch/hour/sq. foot/°F

$$ 1\ \mathrm{W/(m\cdot\ K)}=\cfrac{1}{518.87316166/3600}\ \mathrm{Btu\ (th)\ inch/(h\cdot\ ft^2\cdot\ °F)}=6.94\ \mathrm{Btu\ (th)\ inch/(h\cdot\ ft^2\cdot\ °F)} $$
$ 6.9381117891755\ \mathrm{Btu\ (th)\ inch/(h\cdot\ ft^2\cdot\ °F)} $
Unrounded result
6.9381117891755
$1\ \mathrm{W/(m\cdot\ K)}=\cfrac{1}{518.87316166/3600}\ \mathrm{Btu\ (th)\ inch/(h\cdot\ ft^2\cdot\ °F)}=6.94\ \mathrm{Btu\ (th)\ inch/(h\cdot\ ft^2\cdot\ °F)}$
Equations in LaTeX code
1\ \mathrm{W/(m\cdot\ K)}=\cfrac{1}{518.87316166/3600}\ \mathrm{Btu\ (th)\ inch/(h\cdot\ ft^2\cdot\ °F)}=6.94\ \mathrm{Btu\ (th)\ inch/(h\cdot\ ft^2\cdot\ °F)}
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