Menu

Kilocalorie (IT)/hour/meter/°C to Btu (th) inch/hour/sq. foot/°F

Values for calculation

$ \{\text{Value}\in\mathbb{R}\} $
This set includes all real numbers.
$ \text{Value} $

Thermal conductivity converter

Thermal conductivity converter from kilocalorie (IT)/hour/meter/°C to Btu (th) inch/hour/sq. foot/°F

$$ 1\ \mathrm{kcal\ (IT)/(h\cdot\ m\cdot\ °C)}=\cfrac{{1}\cdot{418.68/60/60\cdot 10}}{518.87316166/3600}\ \mathrm{Btu\ (th)\ inch/(h\cdot\ ft^2\cdot\ °F)}=8.07\ \mathrm{Btu\ (th)\ inch/(h\cdot\ ft^2\cdot\ °F)} $$
$ 8.0690240108111\ \mathrm{Btu\ (th)\ inch/(h\cdot\ ft^2\cdot\ °F)} $
Unrounded result
8.0690240108111
$1\ \mathrm{kcal\ (IT)/(h\cdot\ m\cdot\ °C)}=\cfrac{{1}\cdot{418.68/60/60\cdot 10}}{518.87316166/3600}\ \mathrm{Btu\ (th)\ inch/(h\cdot\ ft^2\cdot\ °F)}=8.07\ \mathrm{Btu\ (th)\ inch/(h\cdot\ ft^2\cdot\ °F)}$
Equations in LaTeX code
1\ \mathrm{kcal\ (IT)/(h\cdot\ m\cdot\ °C)}=\cfrac{{1}\cdot{418.68/60/60\cdot 10}}{518.87316166/3600}\ \mathrm{Btu\ (th)\ inch/(h\cdot\ ft^2\cdot\ °F)}=8.07\ \mathrm{Btu\ (th)\ inch/(h\cdot\ ft^2\cdot\ °F)}
On this page