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Joule/kilogram/K to Btu (IT)/pound/°F

Values for calculation

$ \text{Value} $

Specific heat capacity converter

Specific heat capacity converter from joule/kilogram/K to Btu (IT)/pound/°F

$$ 1\ \mathrm{J/(kg\cdot\ K)}=\cfrac{1}{4186.8}\ \mathrm{Btu\ (IT)/lb/°F}=0.0002388\ \mathrm{Btu\ (IT)/lb/°F} $$