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Tension of a bar of circular cross section with a transverse hole

Tension of a bar of circular cross section with a transverse hole D P P d σ max
Tension of a bar of circular cross section with a transverse hole

Values for calculation

$ \{P\in\mathbb{R}\mid P>0\} $
This set includes all real numbers that are greater than zero. Therefore, it contains only positive numbers. Zero and negative numbers are not included in this set.
$ P $ $ \mathrm{N} $
$ \{d\in\mathbb{R}\mid d>0\} $
This set includes all real numbers that are greater than zero. Therefore, it contains only positive numbers. Zero and negative numbers are not included in this set.
$ d $ $ \mathrm{mm} $
$ \{D\in\mathbb{R}\mid D>0\} $
This set includes all real numbers that are greater than zero. Therefore, it contains only positive numbers. Zero and negative numbers are not included in this set.
$ D $ $ \mathrm{mm} $

Calculation

Stress concentration factor with the nominal stress based on gross area

$$K_{tg}=12.806-42.602\cdot\left(\cfrac{d}{D}\right)+58.333\cdot\left(\cfrac{d}{D}\right)^2$$
$K_{tg}=12.806-42.602\cdot\left(\cfrac{d}{D}\right)+58.333\cdot\left(\cfrac{d}{D}\right)^2$
Equations in LaTeX code
K_{tg}=12.806-42.602\cdot\left(\cfrac{d}{D}\right)+58.333\cdot\left(\cfrac{d}{D}\right)^2

Maximum normal stress

$$σ_{max}=\cfrac{K_{tg}\cdot P}{\left(π/4\right)\cdot D^2}$$
$σ_{max}=\cfrac{K_{tg}\cdot P}{\left(π/4\right)\cdot D^2}$
Equations in LaTeX code
σ_{max}=\cfrac{K_{tg}\cdot P}{\left(π/4\right)\cdot D^2}
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