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Specific internal energy

Values for calculation

$τ$
$γ_τ$
$π$
$γ_π$
$R$ $\mathrm{J\cdot kg^{-1}\cdot K^{-1}}$
$T$ $\mathrm{°C}$
$γ^o_τ$
$γ^r_τ$
$γ^o_π$
$γ^r_π$
$φ_τ$
$\text{Region}$

Calculation

Specific internal energy

$\text{if }\ \text{Region}= 1$
$$u=\left(τ\cdot γ_τ-π\cdot γ_π\right)\cdot R\cdot\left(T+273.15\right)$$
$\text{else if }\ \text{Region}= 2$
$$u=\left(τ\cdot\left(γ^o_τ+γ^r_τ\right)-π\cdot\left(γ^o_π+γ^r_π\right)\right)\cdot R\cdot\left(T+273.15\right)$$
$\text{else if }\ \text{Region}= 3$
$$u=\left(τ\cdot φ_τ\right)\cdot R\cdot\left(T+273.15\right)$$
$\text{else if }\ \text{Region}= 5$
$$u=\left(τ\cdot\left(γ^o_τ+γ^r_τ\right)-π\cdot\left(γ^o_π+γ^r_π\right)\right)\cdot R\cdot\left(T+273.15\right)$$
$\text{else}$
$$u=0$$